1) First you need to know that since it is a vertical line that it is going to be in a straight line.
2) The two points that you have are (-2,5). The vertical line in those set of points is -2
3) So next you need to plug in that number into the equation y=mx + b, 2 goes into the spot of the m since it is the point
4) So your final answer will be y= -2

Exercise 58.

Standard Form
Ax+By=C
Slop-intercept equation
y=mx+b
We have 7y-4x=21 that is standard form, we must change standard form to slop intercept equation, so we changing sides to get y on left side by itself.
7y=4x+21, when we are ganging side of number we must change sine. if on the left side was -4x we get on the right side +4x. Divide everything by 7.
7y=4x+21/7 so we get : y=4x/7 + 3. m = 4x/7 which mean 4 up, 7 over , b=3

Exercise 59.

Exercise 60.

Exercise 61.

the first thing you need to know is what is the slope of the horizontal line ?and what is the equation that i will use to solve it.
because is a horizontal line the slope is 0 and and we use the y=mx+b
y=mx+b
y=0x+(-4)since any number multiply by 0 is 0 than
y=-4

Exercise 62.

First, ask yourself, What is the slope intercept form? Which is Y=Mx+B where, M=slope and B=y intercept.
Second, lets solve... so we want to get all the X's and Y's on a side by themselves where it would look like the slope equation y=Mx+B
3x-6y=48 Let's subtract 3x to both sides to have 6y by itself.
-3x -3x
= -6y=-3x+48
-/6 - /6 -/6 Let's get y by itself, so we would divide -6 to all the numbers in the equation.
we are left with Y= -3x+48
/-6 /-6
Answer is y= 1x-8
/2
Can you tell me which is the slope and y-Intercept by looking at the slope intercept form?
M=1/2 y-intercept= -8

Posted By Da Boss.

English feedback by Johny Polo

Exercise 63.

First Step: lets use our slope intercept form y = mx+b

Second Step: lets plug in and use our given values

point (-3,4) slope -2/3
y = mx + b
4 = -2/3 + -3

*note: m= slope, b= y-intercept*

Third Step: lets solve our equation

4 = -2/3 (-3) + b

-3 is a whole number we must convert it into a fraction by putting it over 1

4 = -2/3 (-3/1) + b

Fourth Step: solve for b

4= 6/3 + b

reduce if possible 6/3 = 2/1 or 2 *note: anything over 1 equals a whole number*

4 = 2 + b

Fifth Step: solve by using opposite operation

4 = 2 + b -2 -2 + b

2 = b

Final Step: plug in your answer using the slope intercept form

y = mx + b

y = -2/3 + 2

FINAL ANSWER IS: y = -2/3 + 2

Your graph should look like this

Notice how the line passes through our y-intercept which is positive 2, and given points (-3,4).

If you're still not sure check your answer by using our slope which is -2/3 (let 2 be the rise and 3 the run)

Start from the given point and move three spaces to the left and two spaces down since we have a negative slope

-ibet arana

Exercise 64.

So first you have to simplify this to standard form by getting a single Y on one side. - 10x - 5y = 20 *Add 10x to each side - 5y = 20 +10x *Divide each side by -5 y = - 4 - 2x y = -2x -4 *The -2 represents the slope, so for every 2 units it goes down, it moves to the right one unit *The -4 represents the y-intercept (or where it crosses the y-axis)

Exercise 65.

The first thing you had to do was make the equation into y=mx+b form. To do this you get the y variable by itself by subtracting 5x from both sides and then dividing by 3. After you do that you get y=-5/3x+5. After that you make a a graph. You start by graphing the y-intersection which you know because of the equation is (0,5). From there you use the slope to figure out where the rest of your points are by moving down 5 points and to the right 3 points. Once you understand how to do the problem it is not that difficult.

## Exercise 56.

## Exercise 57.

1) First you need to know that since it is a vertical line that it is going to be in a straight line.

2) The two points that you have are (-2,5). The vertical line in those set of points is -2

3) So next you need to plug in that number into the equation y=mx + b, 2 goes into the spot of the m since it is the point

4) So your final answer will be y= -2

## Exercise 58.

Standard Form

Ax+By=C

Slop-intercept equation

y=mx+b

We have 7y-4x=21 that is standard form, we must change standard form to slop intercept equation, so we changing sides to get y on left side by itself.

7y=4x+21, when we are ganging side of number we must change sine. if on the left side was -4x we get on the right side +4x. Divide everything by 7.

7y=4x+21/7 so we get : y=4x/7 + 3. m = 4x/7 which mean 4 up, 7 over , b=3

## Exercise 59.

## Exercise 60.

## Exercise 61.

the first thing you need to know is what is the slope of the horizontal line ?and what is the equation that i will use to solve it.

because is a horizontal line the slope is 0 and and we use the y=mx+b

y=mx+b

y=0x+(-4)since any number multiply by 0 is 0 than

y=-4

## Exercise 62.

First, ask yourself, What is the slope intercept form? Which is Y=Mx+B where, M=slope and B=y intercept.

Second, lets solve... so we want to get all the X's and Y's on a side by themselves where it would look like the slope equation y=Mx+B

3x-6y=48 Let's subtract 3x to both sides to have 6y by itself.

-3x -3x

= -6y=-3x+48

-/6 - /6 -/6 Let's get y by itself, so we would divide -6 to all the numbers in the equation.

we are left with Y= -3x+48

/-6 /-6

Answer is y= 1x-8

/2

Can you tell me which is the slope and

y-Intercept by looking at the slope intercept form?M=1/2

y-intercept= -8

Posted By Da Boss.

English feedback by Johny Polo

## Exercise 63.

First Step: lets use our slope intercept formy = mx+b

Second Step: lets plug in and use our given valuespoint (-3,4) slope -2/3

y = mx + b

4 = -2/3 + -3

*note: m= slope, b= y-intercept*Third Step: lets solve our equation4 = -2/3 (-3) + b

-3 is a whole number we must convert it into a fraction by putting it over 14 = -2/3 (-3/1) + b

Fourth Step: solve for b4= 6/3 + b

reduce if possible 6/3 = 2/1 or 2*note: anything over 1 equals a whole number*4 = 2 + b

Fifth Step: solve by using opposite operation4 = 2 + b

-2 -2 + b

2 = b

Final Step: plug in your answer using the slope intercept formy = mx + b

y = -2/3 + 2

FINAL ANSWER IS: y = -2/3 + 2

Your graph should look like thisNotice how the line passes through our y-intercept which is positive 2, and given points (-3,4).If you're still not sure check your answer by using our slope which is -2/3 (let 2 be the rise and 3 the run)Start from the given point and move three spaces to the left and two spaces down since we have a negative slope-ibet arana

## Exercise 64.

So first you have to simplify this to standard form by getting a single Y on one side.

- 10x - 5y = 20

*Add 10x to each side

- 5y = 20 +10x

*Divide each side by -5

y = - 4 - 2x

y = -2x -4

*The -2 represents the slope, so for every 2 units it goes down, it moves to the right one unit

*The -4 represents the y-intercept (or where it crosses the y-axis)

## Exercise 65.

The first thing you had to do was make the equation into y=mx+b form. To do this you get the y variable by itself by subtracting 5x from both sides and then dividing by 3. After you do that you get y=-5/3x+5. After that you make a a graph. You start by graphing the y-intersection which you know because of the equation is (0,5). From there you use the slope to figure out where the rest of your points are by moving down 5 points and to the right 3 points. Once you understand how to do the problem it is not that difficult.

## Exercise 66.