1.+Radicals

Exercise 1.
Factor common terms from 4-2 square root 6 .Factor 2 out of 4-2 square root 6 giving 2 parentheses 2- square root 6. Square root 3 multiplied by 2 square parentheses 2- square root 6.then you distribute square root 3 over 2- square root 6 which gives you square root 3 parentheses 2- square root 6 which equals 2 square root 3 - 3 square root 2. The final answer is 2 parentheses 2 square root 3 - 3 square root 3.

Exercise 2.


6√2- √12 + 5√8 6√2 stays the same because we cannot simplify it any further √12 can be simplified to √4√3 5√8 can be simplified to 5√4√2
 * __First Step__: Let's simplify our given radicals**

6√2- √4√3 + 5√4√2
 * __Second Step__: Let's ** **plug in our simplified radicals**

6√2- 2 √3 + 5 x 2 √2
 * __Third Step__: Let's ** **solve each radical by finding the square root if possible, and if so, we can then remove the radical sign!**

// * note in this case we would only be able to solve for √4=2* //

6√2 + 5 x 2 √2 - 2√3 6√2 + 10√2 - 2√3 16√2 - 2√3
 * __Fourth Step__: Let's combine like terms**

* note keep the same sign of given number as is ex. - 2√3*

16√2 - 2√3
 * __ OUR FINAL ANSWER IS: __**

-ibet arana


 * English feedback by Cyndi. FYI, the word "let's" comes from "let us," so you need the apostrophe because it's a long-forgotten contraction. **