1) First you need to know that since it is a vertical line that it is going to be in a straight line.
2) The two points that you have are (-2,5). The vertical line in those set of points is -2
3) So next you need to plug in that number into the equation y=mx + b, 2 goes into the spot of the m since it is the point
4) So your final answer will be y= -2
Exercise 58.
Standard Form
Ax+By=C
Slop-intercept equation
y=mx+b
We have 7y-4x=21 that is standard form, we must change standard form to slop intercept equation, so we changing sides to get y on left side by itself.
7y=4x+21, when we are ganging side of number we must change sine. if on the left side was -4x we get on the right side +4x. Divide everything by 7.
7y=4x+21/7 so we get : y=4x/7 + 3. m = 4x/7 which mean 4 up, 7 over , b=3
Exercise 59.
Exercise 60.
Exercise 61.
the first thing you need to know is what is the slope of the horizontal line ?and what is the equation that i will use to solve it.
because is a horizontal line the slope is 0 and and we use the y=mx+b
y=mx+b
y=0x+(-4)since any number multiply by 0 is 0 than
y=-4
Exercise 62.
First, ask yourself, What is the slope intercept form? Which is Y=Mx+B where, M=slope and B=y intercept.
Second, lets solve... so we want to get all the X's and Y's on a side by themselves where it would look like the slope equation y=Mx+B
3x-6y=48 Let's subtract 3x to both sides to have 6y by itself.
-3x -3x
= -6y=-3x+48
-/6 - /6 -/6 Let's get y by itself, so we would divide -6 to all the numbers in the equation.
we are left with Y= -3x+48
/-6 /-6
Answer is y= 1x-8
/2
Can you tell me which is the slope and y-Intercept by looking at the slope intercept form?
M=1/2 y-intercept= -8
Posted By Da Boss.
English feedback by Johny Polo
Exercise 63.
First Step: lets use our slope intercept form y = mx+b
Second Step: lets plug in and use our given values
point (-3,4) slope -2/3
y = mx + b
4 = -2/3 + -3
*note: m= slope, b= y-intercept*
Third Step: lets solve our equation
4 = -2/3 (-3) + b
-3 is a whole number we must convert it into a fraction by putting it over 1
4 = -2/3 (-3/1) + b
Fourth Step: solve for b
4= 6/3 + b
reduce if possible 6/3 = 2/1 or 2 *note: anything over 1 equals a whole number*
4 = 2 + b
Fifth Step: solve by using opposite operation
4 = 2 + b -2 -2 + b
2 = b
Final Step: plug in your answer using the slope intercept form
y = mx + b
y = -2/3 + 2
FINAL ANSWER IS: y = -2/3 + 2
Your graph should look like this
Notice how the line passes through our y-intercept which is positive 2, and given points (-3,4).
If you're still not sure check your answer by using our slope which is -2/3 (let 2 be the rise and 3 the run)
Start from the given point and move three spaces to the left and two spaces down since we have a negative slope
-ibet arana
Exercise 64.
So first you have to simplify this to standard form by getting a single Y on one side. - 10x - 5y = 20 *Add 10x to each side - 5y = 20 +10x *Divide each side by -5 y = - 4 - 2x y = -2x -4 *The -2 represents the slope, so for every 2 units it goes down, it moves to the right one unit *The -4 represents the y-intercept (or where it crosses the y-axis)
Exercise 65.
The first thing you had to do was make the equation into y=mx+b form. To do this you get the y variable by itself by subtracting 5x from both sides and then dividing by 3. After you do that you get y=-5/3x+5. After that you make a a graph. You start by graphing the y-intersection which you know because of the equation is (0,5). From there you use the slope to figure out where the rest of your points are by moving down 5 points and to the right 3 points. Once you understand how to do the problem it is not that difficult.
Exercise 56.
Exercise 57.
1) First you need to know that since it is a vertical line that it is going to be in a straight line.
2) The two points that you have are (-2,5). The vertical line in those set of points is -2
3) So next you need to plug in that number into the equation y=mx + b, 2 goes into the spot of the m since it is the point
4) So your final answer will be y= -2
Exercise 58.
Standard Form
Ax+By=C
Slop-intercept equation
y=mx+b
We have 7y-4x=21 that is standard form, we must change standard form to slop intercept equation, so we changing sides to get y on left side by itself.
7y=4x+21, when we are ganging side of number we must change sine. if on the left side was -4x we get on the right side +4x. Divide everything by 7.
7y=4x+21/7 so we get : y=4x/7 + 3. m = 4x/7 which mean 4 up, 7 over , b=3
Exercise 59.
Exercise 60.
Exercise 61.
the first thing you need to know is what is the slope of the horizontal line ?and what is the equation that i will use to solve it.
because is a horizontal line the slope is 0 and and we use the y=mx+b
y=mx+b
y=0x+(-4)since any number multiply by 0 is 0 than
y=-4
Exercise 62.
First, ask yourself, What is the slope intercept form? Which is Y=Mx+B where, M=slope and B=y intercept.
Second, lets solve... so we want to get all the X's and Y's on a side by themselves where it would look like the slope equation y=Mx+B
3x-6y=48 Let's subtract 3x to both sides to have 6y by itself.
-3x -3x
= -6y=-3x+48
-/6 - /6 -/6 Let's get y by itself, so we would divide -6 to all the numbers in the equation.
we are left with Y= -3x+48
/-6 /-6
Answer is y= 1x-8
/2
Can you tell me which is the slope and y-Intercept by looking at the slope intercept form?
M=1/2
y-intercept= -8
Posted By Da Boss.
English feedback by Johny Polo
Exercise 63.
First Step: lets use our slope intercept form
y = mx+b
Second Step: lets plug in and use our given values
point (-3,4) slope -2/3
y = mx + b
4 = -2/3 + -3
*note: m= slope, b= y-intercept*
Third Step: lets solve our equation
4 = -2/3 (-3) + b
-3 is a whole number we must convert it into a fraction by putting it over 1
4 = -2/3 (-3/1) + b
Fourth Step: solve for b
4= 6/3 + b
reduce if possible 6/3 = 2/1 or 2
*note: anything over 1 equals a whole number*
4 = 2 + b
Fifth Step: solve by using opposite operation
4 = 2 + b
-2 -2 + b
2 = b
Final Step: plug in your answer using the slope intercept form
y = mx + b
y = -2/3 + 2
FINAL ANSWER IS: y = -2/3 + 2
-ibet arana
Exercise 64.
So first you have to simplify this to standard form by getting a single Y on one side.
- 10x - 5y = 20
*Add 10x to each side
- 5y = 20 +10x
*Divide each side by -5
y = - 4 - 2x
y = -2x -4
*The -2 represents the slope, so for every 2 units it goes down, it moves to the right one unit
*The -4 represents the y-intercept (or where it crosses the y-axis)
Exercise 65.
The first thing you had to do was make the equation into y=mx+b form. To do this you get the y variable by itself by subtracting 5x from both sides and then dividing by 3. After you do that you get y=-5/3x+5. After that you make a a graph. You start by graphing the y-intersection which you know because of the equation is (0,5). From there you use the slope to figure out where the rest of your points are by moving down 5 points and to the right 3 points. Once you understand how to do the problem it is not that difficult.
Exercise 66.